{"id":97,"date":"2022-05-18T16:36:35","date_gmt":"2022-05-18T16:36:35","guid":{"rendered":"https:\/\/pressbooks.ccconline.org\/accintrostats\/chapter\/measures-of-the-center-of-the-data\/"},"modified":"2022-11-09T16:36:51","modified_gmt":"2022-11-09T16:36:51","slug":"measures-of-the-center-of-the-data","status":"publish","type":"chapter","link":"https:\/\/pressbooks.ccconline.org\/accintrostats\/chapter\/measures-of-the-center-of-the-data\/","title":{"raw":"Chapter 2.4: Measures of the Center of the Data","rendered":"Chapter 2.4: Measures of the Center of the Data"},"content":{"raw":"&nbsp;\r\n<p id=\"element-848\">The \"center\" of a data set is also a way of describing location. The two most widely used measures of the \"center\" of the data are the <span data-type=\"term\">mean<\/span> (average) and the <span data-type=\"term\">median<\/span>. To calculate the <strong>mean weight<\/strong> of 50 people, add the 50 weights together and divide by 50. To find the <strong>median weight<\/strong> of the 50 people, order the data and find the number that splits the data into two equal parts. The median is generally a better measure of the center when there are extreme values or outliers because it is not affected by the precise numerical values of the outliers. The mean is the most common measure of the center.<\/p>\r\n\r\n<div id=\"eip-13\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\"><\/div>\r\n<div data-type=\"title\">NOTE<\/div>\r\n<p id=\"fs-idp62684352\">The words \u201cmean\u201d and \u201caverage\u201d are often used interchangeably. The substitution of one word for the other is common practice. The technical term is \u201carithmetic mean\u201d and \u201caverage\u201d is technically a center location. However, in practice among non-statisticians, \u201caverage\" is commonly accepted for \u201carithmetic mean.\u201d<\/p>\r\n\r\n<\/div>\r\n<p id=\"element-44\">When each value in the data set is not unique, the mean can be calculated by multiplying each distinct value by its frequency and then dividing the sum by the total number of data values. The letter used to represent the <strong>sample mean<\/strong> is an <em data-effect=\"italics\">x<\/em> with a bar over it (pronounced \u201c<em data-effect=\"italics\">x<\/em> bar\u201d): \\(\\overline{x}\\).<\/p>\r\n<p id=\"element-705\">The Greek letter <em data-effect=\"italics\">\u03bc<\/em> (pronounced \"mew\") represents the <strong>population mean<\/strong>. One of the requirements for the <strong>sample mean<\/strong> to be a good estimate of the <strong>population mean<\/strong> is for the sample taken to be truly random.<\/p>\r\n<p id=\"element-228\">To see that both ways of calculating the mean are the same, consider the sample: <span data-type=\"newline\">\r\n<\/span>1; 1; 1; 2; 2; 3; 4; 4; 4; 4; 4<\/p>\r\n\r\n<div id=\"element-46\" data-type=\"equation\">\\(\\overline{x}=\\frac{1+1+1+2+2+3+4+4+4+4+4}{11}=2.7\\)<\/div>\r\n<div data-type=\"equation\">\\(\\overline{x}=\\frac{3\\left(1\\right)+2\\left(2\\right)+1\\left(3\\right)+5\\left(4\\right)}{11}=2.7\\)<\/div>\r\n<p id=\"element-180\">In the second calculation, the frequencies are 3, 2, 1, and 5.<\/p>\r\nYou can quickly find the location of the median by using the expression \\(\\frac{n+1}{2}\\).\r\n<p id=\"element-860\">The letter <em data-effect=\"italics\">n<\/em> is the total number of data values in the sample. If <em data-effect=\"italics\">n<\/em> is an odd number, the median is the middle value of the ordered data (ordered smallest to largest). If <em data-effect=\"italics\">n<\/em> is an even number, the median is equal to the two middle values added together and divided by two after the data has been ordered. For example, if the total number of data values is 97, then \\(\\frac{n+1}{2}\\)= \\(\\frac{97+1}{2}\\) = 49. The median is the 49<sup>th<\/sup> value in the ordered data. If the total number of data values is 100, then \\(\\frac{n+1}{2}\\)= \\(\\frac{100+1}{2}\\) = 50.5. The median occurs midway between the 50<sup>th<\/sup> and 51<sup>st<\/sup> values. The location of the median and the value of the median are <strong>not<\/strong> the same. The upper case letter <em data-effect=\"italics\">M<\/em> is often used to represent the median. The next example illustrates the location of the median and the value of the median.<\/p>\r\n\r\n<div id=\"element-3\" class=\"textbox textbox--examples\" data-type=\"example\">\r\n<div id=\"exer4\" data-type=\"exercise\">\r\n<div id=\"id45306962\" data-type=\"problem\">\r\n<p id=\"element-226\">AIDS data indicating the number of months a patient with AIDS lives after taking a new antibody drug are as follows (smallest to largest): <span data-type=\"newline\">\r\n<\/span>3;\u00a0 4;\u00a0 8;\u00a0 8;\u00a0 10;\u00a0 11;\u00a0 12;\u00a0 13;\u00a0 14;\u00a0 15;\u00a0 15;\u00a0 16;\u00a0 16;\u00a0 17;\u00a0 17;\u00a0 18;\u00a0 21;\u00a0 22;\u00a0 22;\u00a0 24;\u00a0 24;\u00a0 25;\u00a0 26;\u00a0 26;\u00a0 27;\u00a0 27;\u00a0 29;\u00a0 29;\u00a0 31;\u00a0 32;\u00a0 33;\u00a0 33;\u00a0 34;\u00a0 34;\u00a0 35;\u00a0 37;\u00a0 40;\u00a0 44;\u00a0 44;\u00a0 47; <span data-type=\"newline\">\r\n<\/span>Calculate the mean and the median.<\/p>\r\n\r\n<\/div>\r\n<div id=\"id45386042\" data-type=\"solution\">\r\n<p id=\"element-471\">The calculation for the mean is:<\/p>\r\n<p id=\"element-197\">\\(\\overline{x}=\\frac{\\left[3+4+\\left(8\\right)\\left(2\\right)+10+11+12+13+14+\\left(15\\right)\\left(2\\right)+\\left(16\\right)\\left(2\\right)+\\text{...}+35+37+40+\\left(44\\right)\\left(2\\right)+47\\right]}{40}=\\mathrm{23.6}\\)<span data-type=\"newline\">\r\n<\/span>To find the median, <em data-effect=\"italics\">M<\/em>, first use the formula for the location. The location is: <span data-type=\"newline\">\r\n<\/span>\\(\\frac{n+1}{2}=\\frac{40+1}{2}=20.5\\)<span data-type=\"newline\">\r\n<\/span>Starting at the smallest value, the median is located between the 20<sup>th<\/sup> and 21<sup>st<\/sup> values (the two 24s): <span data-type=\"newline\">\r\n<\/span>3;\u00a0 4;\u00a0 8;\u00a0 8;\u00a0 10;\u00a0 11;\u00a0 12;\u00a0 13;\u00a0 14;\u00a0 15;\u00a0 15;\u00a0 16;\u00a0 16;\u00a0 17;\u00a0 17;\u00a0 18;\u00a0 21;\u00a0 22;\u00a0 22;\u00a0 24 ; 24;\u00a0 25;\u00a0 26;\u00a0 26;\u00a0 27;\u00a0 27;\u00a0 29;\u00a0 29;\u00a0 31;\u00a0 32;\u00a0 33;\u00a0 33;\u00a0 34;\u00a0 34;\u00a0 35;\u00a0 37;\u00a0 40;\u00a0 44;\u00a0 44;\u00a0 47;<\/p>\r\n<p id=\"element-904\">\\(M=\\frac{24+24}{2}=24\\)<\/p>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp50763088\" class=\"statistics calculator\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<p id=\"fs-idp54507328\">To find the mean and the median:<\/p>\r\n<p id=\"fs-idp87775312\">Clear list L1. Pres STAT 4:ClrList. Enter 2nd 1 for list L1. Press ENTER.<\/p>\r\n<p id=\"fs-idm47103392\">Enter data into the list editor. Press STAT 1:EDIT.<\/p>\r\n<p id=\"fs-idp45529696\">Put the data values into list L1.<\/p>\r\n<p id=\"fs-idp33349200\">Press STAT and arrow to CALC. Press 1:1-VarStats. Press 2nd 1 for L1 and then ENTER.<\/p>\r\n<p id=\"fs-idp46064432\">Press the down and up arrow keys to scroll.<\/p>\r\n<p id=\"fs-idp50820000\">\\(\\overline{x}\\) = 23.6, <em data-effect=\"italics\">M<\/em> = 24<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idp48953680\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">Try It<\/div>\r\n<div id=\"fs-idm28353888\" data-type=\"exercise\">\r\n<div id=\"fs-idm72704208\" data-type=\"problem\">\r\n<p id=\"fs-idm46796800\">The following data show the number of months patients typically wait on a transplant list before getting surgery. The data are ordered from smallest to largest. Calculate the mean and median.<\/p>\r\n<p id=\"fs-idm114142640\"><span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">1 0\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">13\u00a0 <\/span><span data-type=\"item\">14\u00a0 <\/span><span data-type=\"item\">14\u00a0 <\/span><span data-type=\"item\">15\u00a0 <\/span><span data-type=\"item\">15\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">18\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">22\u00a0 <\/span><span data-type=\"item\">22\u00a0 <\/span><span data-type=\"item\">23\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24<\/span><\/span><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"element-231\" class=\"textbox textbox--examples\" data-type=\"example\">\r\n<div id=\"exer6\" data-type=\"exercise\">\r\n<div id=\"id45393377\" data-type=\"problem\">\r\n<p id=\"element-213\">Suppose that in a small town of 50 people, one person earns \\$5,000,000 per year and the other 49 each earn \\$30,000. Which is the better measure of the \"center\": the mean or the median?<\/p>\r\n\r\n<\/div>\r\n<div id=\"id45393396\" data-type=\"solution\">\r\n<p id=\"element-444\">\\(\\overline{x}=\\frac{5,000,000+49\\left(30,000\\right)}{50}=129,400\\)<\/p>\r\n<em data-effect=\"italics\">M<\/em> = 30,000\r\n<p id=\"element-831\">(There are 49 people who earn \\$30,000 and one person who earns \\$5,000,000.)<\/p>\r\nThe median is a better measure of the \"center\" than the mean because 49 of the values are 30,000 and one is 5,000,000. The 5,000,000 is an outlier. The 30,000 gives us a better sense of the middle of the data.\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp18783360\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">Try It<\/div>\r\n<div id=\"fs-idm79009152\" data-type=\"exercise\">\r\n<div id=\"fs-idm79009024\" data-type=\"problem\">\r\n<p id=\"fs-idm10019504\">In a sample of 60 households, one house is worth \\$2,500,000. Half of the rest are worth \\$280,000, and all the others are worth \\$315,000. Which is the better measure of the \u201ccenter\u201d: the mean or the median?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"element-584\">Another measure of the center is the mode. The <span data-type=\"term\">mode<\/span> is the most frequent value. There can be more than one mode in a data set as long as those values have the same frequency and that frequency is the highest. A data set with two modes is called bimodal.<\/p>\r\n\r\n<div id=\"element-114\" class=\"textbox textbox--examples\" data-type=\"example\">\r\n<p id=\"element-639\">Statistics exam scores for 20 students are as follows:<\/p>\r\n<p id=\"element-104\"><span id=\"set-536\" data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">50\u00a0 <\/span><span data-type=\"item\">53\u00a0 <\/span><span data-type=\"item\">59\u00a0 <\/span><span data-type=\"item\">59\u00a0 <\/span><span data-type=\"item\">63\u00a0 <\/span><span data-type=\"item\">63\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">76\u00a0 <\/span><span data-type=\"item\">78\u00a0 <\/span><span data-type=\"item\">81\u00a0 <\/span><span data-type=\"item\">83\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">90\u00a0 <\/span><span data-type=\"item\">93<\/span><\/span><\/p>\r\n\r\n<div id=\"exer3\" data-type=\"exercise\">\r\n<div id=\"id44835721\" data-type=\"problem\">\r\n<p id=\"element-32535\">Find the mode.<\/p>\r\n\r\n<\/div>\r\n<div id=\"id44835735\" data-type=\"solution\">\r\n<p id=\"element-76\">The most frequent score is 72, which occurs five times. Mode = 72.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp45793968\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">Try It<\/div>\r\n<div id=\"fs-idm24402032\" data-type=\"exercise\">\r\n<div id=\"fs-idm24643648\" data-type=\"problem\">\r\n<p id=\"fs-idp74555792\">The number of books checked out from the library from 25 students are as follows:<\/p>\r\n<p id=\"fs-idm901328\"><span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">1\u00a0 <\/span><span data-type=\"item\">2\u00a0 <\/span><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">12<\/span><\/span><span data-type=\"newline\">\r\n<\/span>Find the mode.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"element-725\" class=\"textbox textbox--examples\" data-type=\"example\">\r\n<p id=\"element-622\">Five real estate exam scores are 430, 430, 480, 480, 495. The data set is bimodal because the scores 430 and 480 each occur twice.<\/p>\r\n<p id=\"element-353\">When is the mode the best measure of the \"center\"? Consider a weight loss program that advertises a mean weight loss of six pounds the first week of the program. The mode might indicate that most people lose two pounds the first week, making the program less appealing.<\/p>\r\n\r\n<div data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">NOTE<\/div>\r\n<p id=\"fs-idm78257648\">The mode can be calculated for qualitative data as well as for quantitative data. For example, if the data set is: red, red, red, green, green, yellow, purple, black, blue, the mode is red.<\/p>\r\n\r\n<\/div>\r\n<p id=\"element-660\" class=\"finger\">Statistical software will easily calculate the mean, the median, and the mode. Some graphing calculators can also make these calculations. In the real world, people make these calculations using software.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idp55881696\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">Try It<\/div>\r\n<div id=\"fs-idm2098096\" data-type=\"exercise\">\r\n<div id=\"fs-idm2097968\" data-type=\"problem\">\r\n<p id=\"fs-idm5923360\">Five credit scores are 680, 680, 700, 720, 720. The data set is bimodal because the scores 680 and 720 each occur twice. Consider the annual earnings of workers at a factory. The mode is \\$25,000 and occurs 150 times out of 301. The median is \\$50,000 and the mean is \\$47,500. What would be the best measure of the \u201ccenter\u201d?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"element-282\" class=\"bc-section section\" data-depth=\"1\"><\/div>\r\n<div id=\"eip-529\" class=\"bc-section section\" data-depth=\"1\">\r\n\r\n&nbsp;\r\n<p id=\"eip-309\">A <strong>statistic<\/strong> is a number calculated from a sample. Statistic examples include the mean, the median and the mode as well as others. The sample mean \\(\\overline{x}\\) is an example of a statistic which estimates the population mean <em data-effect=\"italics\">\u03bc<\/em>.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idp28527728\" class=\"bc-section section\" data-depth=\"1\">\r\n<h3 data-type=\"title\">Calculating the Mean of Grouped Frequency Tables<\/h3>\r\n<p id=\"fs-idp16870784\">When only grouped data is available, you do not know the individual data values (we only know intervals and interval frequencies); therefore, you cannot compute an exact mean for the data set. What we must do is estimate the actual mean by calculating the mean of a frequency table. A frequency table is a data representation in which grouped data is displayed along with the corresponding frequencies. To calculate the mean from a grouped frequency table we can apply the basic definition of mean: <em data-effect=\"italics\">mean<\/em> = \\(\\frac{data\\text{\u00a0}sum}{number\\text{\u00a0}of\\text{\u00a0}data\\text{\u00a0}values}\\) We simply need to modify the definition to fit within the restrictions of a frequency table.<\/p>\r\n<p id=\"fs-idp28261664\">Since we do not know the individual data values we can instead find the midpoint of each interval. The midpoint is \\(\\frac{lower\\text{\u00a0}boundary+upper\\text{\u00a0}boundary}{2}\\). We can now modify the mean definition to be \\(Mean\\text{\u00a0}of\\text{\u00a0}Frequency\\text{\u00a0}Table=\\frac{\\sum fm}{\\sum f}\\) where <em data-effect=\"italics\">f<\/em> = the frequency of the interval and <em data-effect=\"italics\">m<\/em> = the midpoint of the interval.<\/p>\r\n\r\n<div id=\"fs-idp59127680\" class=\"textbox textbox--examples\" data-type=\"example\">\r\n<div id=\"fs-idp61839840\" data-type=\"exercise\">\r\n<div id=\"fs-idp47622112\" data-type=\"problem\">\r\n<p id=\"fs-idm6896112\">A frequency table displaying professor Blount\u2019s last statistic test is shown. Find the best estimate of the class mean.<\/p>\r\n\r\n<table id=\"fs-idp32456976\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Grade Interval<\/th>\r\n<th>Number of Students<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>50\u201356.5<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>56.5\u201362.5<\/td>\r\n<td>0<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>62.5\u201368.5<\/td>\r\n<td>4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>68.5\u201374.5<\/td>\r\n<td>4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>74.5\u201380.5<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>80.5\u201386.5<\/td>\r\n<td>3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>86.5\u201392.5<\/td>\r\n<td>4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>92.5\u201398.5<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"fs-idp56820112\" data-type=\"solution\">\r\n<ul id=\"fs-idp26414448\">\r\n \t<li>Find the midpoints for all intervals<\/li>\r\n<\/ul>\r\n<table id=\"fs-idp15194576\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Grade Interval<\/th>\r\n<th>Midpoint<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>50\u201356.5<\/td>\r\n<td>53.25<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>56.5\u201362.5<\/td>\r\n<td>59.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>62.5\u201368.5<\/td>\r\n<td>65.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>68.5\u201374.5<\/td>\r\n<td>71.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>74.5\u201380.5<\/td>\r\n<td>77.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>80.5\u201386.5<\/td>\r\n<td>83.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>86.5\u201392.5<\/td>\r\n<td>89.5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>92.5\u201398.5<\/td>\r\n<td>95.5<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<ul id=\"fs-idp72598816\">\r\n \t<li>Calculate the sum of the product of each interval frequency and midpoint.\\({\\sum }^{\\text{\u200b}}fm\\)\\(53.25\\left(1\\right)+59.5\\left(0\\right)+65.5\\left(4\\right)+71.5\\left(4\\right)+77.5\\left(2\\right)+83.5\\left(3\\right)+89.5\\left(4\\right)+95.5\\left(1\\right)=1460.25\\)<\/li>\r\n \t<li>\\(\\mu =\\frac{\\sum fm}{\\sum f}=\\frac{1460.25}{19}=76.86\\)<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idm52755520\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\r\n<div data-type=\"title\">Try It<\/div>\r\n<div id=\"fs-idp22476928\" data-type=\"exercise\">\r\n<div id=\"fs-idp50951968\" data-type=\"problem\">\r\n<p id=\"fs-idm11216000\">Maris conducted a study on the effect that playing video games has on memory recall. As part of her study, she compiled the following data:<\/p>\r\n\r\n<table id=\"fs-idm6918832\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Hours Teenagers Spend on Video Games<\/th>\r\n<th>Number of Teenagers<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>0\u20133.5<\/td>\r\n<td>3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>3.5\u20137.5<\/td>\r\n<td>7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>7.5\u201311.5<\/td>\r\n<td>12<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>11.5\u201315.5<\/td>\r\n<td>7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>15.5\u201319.5<\/td>\r\n<td>9<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<p id=\"fs-idp10596832\">What is the best estimate for the mean number of hours spent playing video games?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp2891248\" class=\"footnotes\" data-depth=\"1\">\r\n<h3 data-type=\"title\">References<\/h3>\r\n<p id=\"fs-idp41166864\">Data from The World Bank, available online at http:\/\/www.worldbank.org (accessed April 3, 2013).<\/p>\r\n<p id=\"fs-idp18149184\">\u201cDemographics: Obesity \u2013 adult prevalence rate.\u201d Indexmundi. Available online at http:\/\/www.indexmundi.com\/g\/r.aspx?t=50&amp;v=2228&amp;l=en (accessed April 3, 2013).<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idm7033248\" class=\"summary\" data-depth=\"1\">\r\n<h3 data-type=\"title\">Chapter Review<\/h3>\r\n<p id=\"fs-idm18283152\">The mean and the median can be calculated to help you find the \"center\" of a data set. The mean is the best estimate for the actual data set, but the median is the best measurement when a data set contains several outliers or extreme values. The mode will tell you the most frequently occuring datum (or data) in your data set. The mean, median, and mode are extremely helpful when you need to analyze your data, but if your data set consists of ranges which lack specific values, the mean may seem impossible to calculate. However, the mean can be approximated if you add the lower boundary with the upper boundary and divide by two to find the midpoint of each interval. Multiply each midpoint by the number of values found in the corresponding range. Divide the sum of these values by the total number of data values in the set.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idm345328\" class=\"formula-review\" data-depth=\"1\">\r\n<h3 data-type=\"title\">Formula Review<\/h3>\r\n<p id=\"fs-idp28375264\">\\(\\mu =\\frac{\\sum fm}{\\sum f}\\) Where <em data-effect=\"italics\">f<\/em> = interval frequencies and <em data-effect=\"italics\">m<\/em> = interval midpoints.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idp67676496\" class=\"practice\" data-depth=\"1\">\r\n<div id=\"fs-idp11191056\" data-type=\"exercise\">\r\n<div id=\"fs-idp72176256\" data-type=\"problem\">\r\n<p id=\"fs-idp29942336\">Find the mean for the following frequency tables.<\/p>\r\n\r\n<ol id=\"fs-idp39027888\" type=\"a\">\r\n \t<li>\r\n<table id=\"fs-idp4665840\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Grade<\/th>\r\n<th>Frequency<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>49.5\u201359.5<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>59.5\u201369.5<\/td>\r\n<td>3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>69.5\u201379.5<\/td>\r\n<td>8<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>79.5\u201389.5<\/td>\r\n<td>12<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>89.5\u201399.5<\/td>\r\n<td>5<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n \t<li>\r\n<table id=\"fs-idp21318848\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Daily Low Temperature<\/th>\r\n<th>Frequency<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>49.5\u201359.5<\/td>\r\n<td>53<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>59.5\u201369.5<\/td>\r\n<td>32<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>69.5\u201379.5<\/td>\r\n<td>15<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>79.5\u201389.5<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>89.5\u201399.5<\/td>\r\n<td>0<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n \t<li>\r\n<table id=\"fs-idp49142800\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Points per Game<\/th>\r\n<th>Frequency<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>49.5\u201359.5<\/td>\r\n<td>14<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>59.5\u201369.5<\/td>\r\n<td>32<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>69.5\u201379.5<\/td>\r\n<td>15<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>79.5\u201389.5<\/td>\r\n<td>23<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>89.5\u201399.5<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"eip-193\"><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> The following data show the lengths of boats moored in a marina. The data are ordered from smallest to largest: <span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">16\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">20\u00a0 <\/span><span data-type=\"item\">20\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">23\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">26\u00a0 <\/span><span data-type=\"item\">26\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">28\u00a0 <\/span><span data-type=\"item\">29\u00a0 <\/span><span data-type=\"item\">30\u00a0 <\/span><span data-type=\"item\">32\u00a0 <\/span><span data-type=\"item\">33\u00a0 <\/span><span data-type=\"item\">33\u00a0 <\/span><span data-type=\"item\">34\u00a0 <\/span><span data-type=\"item\">35\u00a0 <\/span><span data-type=\"item\">37\u00a0 <\/span><span data-type=\"item\">39\u00a0 <\/span><span data-type=\"item\">40<\/span><\/span><\/p>\r\n\r\n<div id=\"fs-idp3713376\" data-type=\"exercise\">\r\n<div id=\"fs-idp45051248\" data-type=\"problem\">\r\n<p id=\"fs-idp72372672\">Calculate the mean.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idp54737296\" data-type=\"solution\">\r\n<p id=\"fs-idp31759600\">Mean: 16 + 17 + 19 + 20 + 20 + 21 + 23 + 24 + 25 + 25 + 25 + 26 + 26 + 27 + 27 + 27 + 28 + 29 + 30 + 32 + 33 + 33 + 34 + 35 + 37 + 39 + 40 = 738;<\/p>\r\n<p id=\"fs-idp62762816\">\\(\\frac{738}{27}\\) = 27.33<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp23937584\" data-type=\"exercise\">\r\n<div id=\"fs-idm6016496\" data-type=\"problem\">\r\n<p id=\"fs-idp65368416\">Identify the median.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idm35941040\" data-type=\"exercise\">\r\n<div id=\"fs-idp155088\" data-type=\"problem\">\r\n<p id=\"fs-idp27706128\">Identify the mode.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-idm53012848\" data-type=\"solution\">\r\n<p id=\"fs-idp8367280\">The most frequent lengths are 25 and 27, which occur three times. Mode = 25, 27<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-idp43142960\"><span data-type=\"newline\">\r\n<\/span><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people answered that they generally sell three cars; nineteen generally sell four cars; twelve generally sell five cars; nine generally sell six cars; eleven generally sell seven cars. Calculate the following:<\/p>\r\n\r\n<div data-type=\"exercise\">\r\n<div id=\"id5461618\" data-type=\"problem\">\r\n\r\nsample mean = \\(\\overline{x}\\) = _______\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"eip-83\" data-type=\"exercise\">\r\n<div id=\"eip-718\" data-type=\"problem\">\r\n<p id=\"eip-423\">median = _______<\/p>\r\n\r\n<\/div>\r\n<div id=\"eip-288\" data-type=\"solution\">\r\n<p id=\"eip-669\">4<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"eip-630\" data-type=\"exercise\">\r\n<div id=\"eip-353\" data-type=\"problem\">\r\n<p id=\"eip-212\">mode = _______<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idm59277808\" class=\"free-response\" data-depth=\"1\">\r\n<h3 data-type=\"title\">Homework<\/h3>\r\n<div data-type=\"exercise\">\r\n<div data-type=\"problem\">\r\n<p id=\"eip-474\">1) \u00a0<a class=\"autogenerated-content\" href=\"#eip-456s\">(Figure)<\/a> gives the percent of children under five considered to be underweight. What is the best estimate for the mean percentage of underweight children?<\/p>\r\n\r\n<table id=\"eip-456s\" summary=\"Table....\">\r\n<thead>\r\n<tr>\r\n<th>Percent of Underweight Children<\/th>\r\n<th>Number of Countries<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>16\u201321.45<\/td>\r\n<td>23<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>21.45\u201326.9<\/td>\r\n<td>4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>26.9\u201332.35<\/td>\r\n<td>9<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>32.35\u201337.8<\/td>\r\n<td>7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>37.8\u201343.25<\/td>\r\n<td>6<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>43.25\u201348.7<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"eip-492\" data-type=\"solution\">\r\n\r\n&nbsp;\r\n<p id=\"eip-506\">2)\u00a0 The most obese countries in the world have obesity rates that range from 11.4% to 74.6%. This data is summarized in the following table.<\/p>\r\n\r\n<table id=\"eip-456\" summary=\"Table....\">\r\n<thead>\r\n<tr>\r\n<th>Percent of Population Obese<\/th>\r\n<th>Number of Countries<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>11.4\u201320.45<\/td>\r\n<td>29<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>20.45\u201329.45<\/td>\r\n<td>13<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>29.45\u201338.45<\/td>\r\n<td>4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>38.45\u201347.45<\/td>\r\n<td>0<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>47.45\u201356.45<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>56.45\u201365.45<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>65.45\u201374.45<\/td>\r\n<td>0<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>74.45\u201383.45<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<ol id=\"eip-idm42348400\" type=\"a\">\r\n \t<li>What is the best estimate of the average obesity percentage for these countries?<\/li>\r\n \t<li>The United States has an average obesity rate of 33.9%. Is this rate above average or below?<\/li>\r\n \t<li>How does the United States compare to other countries?<\/li>\r\n<\/ol>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idm1725088\" class=\"bring-together-homework\" data-depth=\"1\">\r\n<h3 data-type=\"title\">Bringing It Together<\/h3>\r\n<div id=\"element-832\" data-type=\"exercise\">\r\n<div id=\"id6092616\" data-type=\"problem\">\r\n<div id=\"eip-idm179364784\" class=\"bc-figure figure\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-idm4887840\"><em data-effect=\"italics\">Use the following information to answer the next three exercises<\/em>: We are interested in the number of years students in a particular elementary statistics class have lived in California. The information in the following table is from the entire section.<\/p>\r\n\r\n<table id=\"element-368\" summary=\"This table presents the number of years students in a statistics class have lived in California. The first column lists the number of years and the second column lists the frequency.\">\r\n<thead>\r\n<tr>\r\n<th>Number of years<\/th>\r\n<th>Frequency<\/th>\r\n<th>Number of years<\/th>\r\n<th>Frequency<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tfoot>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Total = 20<\/td>\r\n<\/tr>\r\n<\/tfoot>\r\n<tbody>\r\n<tr>\r\n<td>7<\/td>\r\n<td>1<\/td>\r\n<td>22<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>14<\/td>\r\n<td>3<\/td>\r\n<td>23<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>15<\/td>\r\n<td>1<\/td>\r\n<td>26<\/td>\r\n<td>1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>18<\/td>\r\n<td>1<\/td>\r\n<td>40<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>19<\/td>\r\n<td>4<\/td>\r\n<td>42<\/td>\r\n<td>2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>20<\/td>\r\n<td>3<\/td>\r\n<td><\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<div data-type=\"exercise\">\r\n<div id=\"id4699277\" data-type=\"problem\">\r\n\r\n3)\u00a0 What is the <em data-effect=\"italics\">IQR<\/em>?\r\n<ol id=\"ni1\" type=\"a\" data-mark-suffix=\".\">\r\n \t<li>8<\/li>\r\n \t<li>11<\/li>\r\n \t<li>15<\/li>\r\n \t<li>35<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6016838\" data-type=\"solution\">\r\n<p id=\"element-991\"><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div data-type=\"exercise\">\r\n<div id=\"id4942656\" data-type=\"problem\">\r\n<p id=\"element-780\">4)\u00a0 What is the mode?<\/p>\r\n\r\n<ol id=\"ni2\" type=\"a\" data-mark-suffix=\".\">\r\n \t<li>19<\/li>\r\n \t<li>19.5<\/li>\r\n \t<li>14 and 20<\/li>\r\n \t<li>22.65<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"element-346\" data-type=\"exercise\">\r\n<div id=\"id5971682\" data-type=\"problem\">\r\n\r\n&nbsp;\r\n\r\n5)\u00a0 Is this a sample or the entire population?\r\n<ol id=\"ni3\" type=\"a\" data-mark-suffix=\".\">\r\n \t<li>sample<\/li>\r\n \t<li>entire population<\/li>\r\n \t<li>neither<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id4081124\" data-type=\"solution\">\r\n<p id=\"element-366\"><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"JavErc\">6) Javier and Ercilia are supervisors at a shopping mall. Each was given the task of estimating the mean distance that shoppers live from the mall. They each randomly surveyed 100 shoppers. The samples yielded the following information.<\/p>\r\n\r\n<table summary=\"This table presents two shopping mall supervisors and their estimations of the mean distance shoppers live from the mall. Javier's data is in the second column and Ercilia is in the third column. The first row is for sample means and the second row is for standard deviations.\">\r\n<thead>\r\n<tr>\r\n<th><\/th>\r\n<th>Javier<\/th>\r\n<th>Ercilia<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>\\(\\overline{x}\\)<\/td>\r\n<td>6.0 miles<\/td>\r\n<td>6.0 miles<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\\(s\\)<\/td>\r\n<td>4.0 miles<\/td>\r\n<td>7.0 miles<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<ol type=\"a\">\r\n \t<li>How can you determine which survey was correct ?<\/li>\r\n \t<li>Explain what the difference in the results of the surveys implies about the data.<\/li>\r\n \t<li>If the two histograms depict the distribution of values for each supervisor, which one depicts Ercilia's sample? How do you know?<span data-type=\"newline\">\r\n<\/span>\r\n<div id=\"eip-idm218452576\" class=\"bc-figure figure\"><span id=\"id8387446\" data-type=\"media\" data-display=\"block\" data-alt=\"This shows two histograms. The first histogram shows a fairly symmetrical distribution with a mode of 6. The second histogram shows a uniform distribution.\"><img src=\"https:\/\/pressbooks.ccconline.org\/acccomposition1\/wp-content\/uploads\/sites\/83\/2022\/05\/fig-ch02_13_09-1.jpg\" alt=\"This shows two histograms. The first histogram shows a fairly symmetrical distribution with a mode of 6. The second histogram shows a uniform distribution.\" width=\"450\" data-media-type=\"image\/jpg\" \/><\/span><\/div><\/li>\r\n \t<li>If the two box plots depict the distribution of values for each supervisor, which one depicts Ercilia\u2019s sample? How do you know?<span data-type=\"newline\">\r\n<\/span>\r\n<div id=\"eip-idm179364784\" class=\"bc-figure figure\"><span id=\"id8629835\" data-type=\"media\" data-display=\"block\" data-alt=\"This shows two horizontal boxplots. The first boxplot is graphed over a number line from 0 to 21. The first whisker extends from 0 to 1. The box begins at the first quartile, 1, and ends at the third quartile, 14. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 21. The second boxplot is graphed over a number line from 0 to 12. The first whisker extends from 0 to 4. The box begins at the first quartile, 4, and ends at the third quartile, 9. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 12.\"><img src=\"https:\/\/pressbooks.ccconline.org\/acccomposition1\/wp-content\/uploads\/sites\/83\/2022\/08\/fig-ch02_13_10-1.jpg\" alt=\"This shows two horizontal boxplots. The first boxplot is graphed over a number line from 0 to 21. The first whisker extends from 0 to 1. The box begins at the first quartile, 1, and ends at the third quartile, 14. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 21. The second boxplot is graphed over a number line from 0 to 12. The first whisker extends from 0 to 4. The box begins at the first quartile, 4, and ends at the third quartile, 9. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 12.\" width=\"450\" data-media-type=\"image\/jpg\" \/><\/span><\/div><\/li>\r\n<\/ol>\r\n<div id=\"element-346\" data-type=\"exercise\">\r\n<div id=\"id4081124\" data-type=\"solution\">\r\n\r\n<strong>Answers to odd Questions<\/strong>\r\n\r\n1)\u00a0 The mean percentage, \\(\\overline{x}=\\frac{1328.65}{50}=26.75\\)\r\n\r\n3) a\r\n\r\n5) b\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox shaded\" data-type=\"glossary\">\r\n<h3 data-type=\"glossary-title\">Glossary<\/h3>\r\n<dl id=\"fs-idm7751856\">\r\n \t<dt>Frequency Table<\/dt>\r\n \t<dd id=\"fs-idp28775440\">a data representation in which grouped data is displayed along with the corresponding frequencies<\/dd>\r\n<\/dl>\r\n<dl id=\"mean\">\r\n \t<dt>Mean<\/dt>\r\n \t<dd id=\"id10578364\">a number that measures the central tendency of the data; a common name for mean is 'average.' The term 'mean' is a shortened form of 'arithmetic mean.' By definition, the mean for a sample (denoted by \\(\\overline{x}\\)) is \\(\\overline{x}\\text{\u00a0}=\\text{\u00a0}\\frac{\\text{Sum\u00a0of\u00a0all\u00a0values\u00a0in\u00a0the\u00a0sample}}{\\text{Number\u00a0of\u00a0values\u00a0in\u00a0the\u00a0sample}}\\), and the mean for a population (denoted by <em data-effect=\"italics\">\u03bc<\/em>) is \\(\\mu =\\frac{\\text{Sum\u00a0of\u00a0all\u00a0values\u00a0in\u00a0the\u00a0population}}{\\text{Number\u00a0of\u00a0values\u00a0in\u00a0the\u00a0population}}\\).<\/dd>\r\n<\/dl>\r\n<dl id=\"median\">\r\n \t<dt>Median<\/dt>\r\n \t<dd id=\"id44836016\">a number that separates ordered data into halves; half the values are the same number or smaller than the median and half the values are the same number or larger than the median. The median may or may not be part of the data.<\/dd>\r\n<\/dl>\r\n<dl id=\"fs-idp5033152\">\r\n \t<dt>Midpoint<\/dt>\r\n \t<dd id=\"fs-idp75012256\">the mean of an interval in a frequency table<\/dd>\r\n<\/dl>\r\n<dl id=\"mode\">\r\n \t<dt>Mode<\/dt>\r\n \t<dd id=\"id44836043\">the value that appears most frequently in a set of data<\/dd>\r\n<\/dl>\r\n<\/div>","rendered":"<p>&nbsp;<\/p>\n<p id=\"element-848\">The &#8220;center&#8221; of a data set is also a way of describing location. The two most widely used measures of the &#8220;center&#8221; of the data are the <span data-type=\"term\">mean<\/span> (average) and the <span data-type=\"term\">median<\/span>. To calculate the <strong>mean weight<\/strong> of 50 people, add the 50 weights together and divide by 50. To find the <strong>median weight<\/strong> of the 50 people, order the data and find the number that splits the data into two equal parts. The median is generally a better measure of the center when there are extreme values or outliers because it is not affected by the precise numerical values of the outliers. The mean is the most common measure of the center.<\/p>\n<div id=\"eip-13\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\"><\/div>\n<div data-type=\"title\">NOTE<\/div>\n<p id=\"fs-idp62684352\">The words \u201cmean\u201d and \u201caverage\u201d are often used interchangeably. The substitution of one word for the other is common practice. The technical term is \u201carithmetic mean\u201d and \u201caverage\u201d is technically a center location. However, in practice among non-statisticians, \u201caverage&#8221; is commonly accepted for \u201carithmetic mean.\u201d<\/p>\n<\/div>\n<p id=\"element-44\">When each value in the data set is not unique, the mean can be calculated by multiplying each distinct value by its frequency and then dividing the sum by the total number of data values. The letter used to represent the <strong>sample mean<\/strong> is an <em data-effect=\"italics\">x<\/em> with a bar over it (pronounced \u201c<em data-effect=\"italics\">x<\/em> bar\u201d): \\(\\overline{x}\\).<\/p>\n<p id=\"element-705\">The Greek letter <em data-effect=\"italics\">\u03bc<\/em> (pronounced &#8220;mew&#8221;) represents the <strong>population mean<\/strong>. One of the requirements for the <strong>sample mean<\/strong> to be a good estimate of the <strong>population mean<\/strong> is for the sample taken to be truly random.<\/p>\n<p id=\"element-228\">To see that both ways of calculating the mean are the same, consider the sample: <span data-type=\"newline\"><br \/>\n<\/span>1; 1; 1; 2; 2; 3; 4; 4; 4; 4; 4<\/p>\n<div id=\"element-46\" data-type=\"equation\">\\(\\overline{x}=\\frac{1+1+1+2+2+3+4+4+4+4+4}{11}=2.7\\)<\/div>\n<div data-type=\"equation\">\\(\\overline{x}=\\frac{3\\left(1\\right)+2\\left(2\\right)+1\\left(3\\right)+5\\left(4\\right)}{11}=2.7\\)<\/div>\n<p id=\"element-180\">In the second calculation, the frequencies are 3, 2, 1, and 5.<\/p>\n<p>You can quickly find the location of the median by using the expression \\(\\frac{n+1}{2}\\).<\/p>\n<p id=\"element-860\">The letter <em data-effect=\"italics\">n<\/em> is the total number of data values in the sample. If <em data-effect=\"italics\">n<\/em> is an odd number, the median is the middle value of the ordered data (ordered smallest to largest). If <em data-effect=\"italics\">n<\/em> is an even number, the median is equal to the two middle values added together and divided by two after the data has been ordered. For example, if the total number of data values is 97, then \\(\\frac{n+1}{2}\\)= \\(\\frac{97+1}{2}\\) = 49. The median is the 49<sup>th<\/sup> value in the ordered data. If the total number of data values is 100, then \\(\\frac{n+1}{2}\\)= \\(\\frac{100+1}{2}\\) = 50.5. The median occurs midway between the 50<sup>th<\/sup> and 51<sup>st<\/sup> values. The location of the median and the value of the median are <strong>not<\/strong> the same. The upper case letter <em data-effect=\"italics\">M<\/em> is often used to represent the median. The next example illustrates the location of the median and the value of the median.<\/p>\n<div id=\"element-3\" class=\"textbox textbox--examples\" data-type=\"example\">\n<div id=\"exer4\" data-type=\"exercise\">\n<div id=\"id45306962\" data-type=\"problem\">\n<p id=\"element-226\">AIDS data indicating the number of months a patient with AIDS lives after taking a new antibody drug are as follows (smallest to largest): <span data-type=\"newline\"><br \/>\n<\/span>3;\u00a0 4;\u00a0 8;\u00a0 8;\u00a0 10;\u00a0 11;\u00a0 12;\u00a0 13;\u00a0 14;\u00a0 15;\u00a0 15;\u00a0 16;\u00a0 16;\u00a0 17;\u00a0 17;\u00a0 18;\u00a0 21;\u00a0 22;\u00a0 22;\u00a0 24;\u00a0 24;\u00a0 25;\u00a0 26;\u00a0 26;\u00a0 27;\u00a0 27;\u00a0 29;\u00a0 29;\u00a0 31;\u00a0 32;\u00a0 33;\u00a0 33;\u00a0 34;\u00a0 34;\u00a0 35;\u00a0 37;\u00a0 40;\u00a0 44;\u00a0 44;\u00a0 47; <span data-type=\"newline\"><br \/>\n<\/span>Calculate the mean and the median.<\/p>\n<\/div>\n<div id=\"id45386042\" data-type=\"solution\">\n<p id=\"element-471\">The calculation for the mean is:<\/p>\n<p id=\"element-197\">\\(\\overline{x}=\\frac{\\left[3+4+\\left(8\\right)\\left(2\\right)+10+11+12+13+14+\\left(15\\right)\\left(2\\right)+\\left(16\\right)\\left(2\\right)+\\text{&#8230;}+35+37+40+\\left(44\\right)\\left(2\\right)+47\\right]}{40}=\\mathrm{23.6}\\)<span data-type=\"newline\"><br \/>\n<\/span>To find the median, <em data-effect=\"italics\">M<\/em>, first use the formula for the location. The location is: <span data-type=\"newline\"><br \/>\n<\/span>\\(\\frac{n+1}{2}=\\frac{40+1}{2}=20.5\\)<span data-type=\"newline\"><br \/>\n<\/span>Starting at the smallest value, the median is located between the 20<sup>th<\/sup> and 21<sup>st<\/sup> values (the two 24s): <span data-type=\"newline\"><br \/>\n<\/span>3;\u00a0 4;\u00a0 8;\u00a0 8;\u00a0 10;\u00a0 11;\u00a0 12;\u00a0 13;\u00a0 14;\u00a0 15;\u00a0 15;\u00a0 16;\u00a0 16;\u00a0 17;\u00a0 17;\u00a0 18;\u00a0 21;\u00a0 22;\u00a0 22;\u00a0 24 ; 24;\u00a0 25;\u00a0 26;\u00a0 26;\u00a0 27;\u00a0 27;\u00a0 29;\u00a0 29;\u00a0 31;\u00a0 32;\u00a0 33;\u00a0 33;\u00a0 34;\u00a0 34;\u00a0 35;\u00a0 37;\u00a0 40;\u00a0 44;\u00a0 44;\u00a0 47;<\/p>\n<p id=\"element-904\">\\(M=\\frac{24+24}{2}=24\\)<\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp50763088\" class=\"statistics calculator\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<p id=\"fs-idp54507328\">To find the mean and the median:<\/p>\n<p id=\"fs-idp87775312\">Clear list L1. Pres STAT 4:ClrList. Enter 2nd 1 for list L1. Press ENTER.<\/p>\n<p id=\"fs-idm47103392\">Enter data into the list editor. Press STAT 1:EDIT.<\/p>\n<p id=\"fs-idp45529696\">Put the data values into list L1.<\/p>\n<p id=\"fs-idp33349200\">Press STAT and arrow to CALC. Press 1:1-VarStats. Press 2nd 1 for L1 and then ENTER.<\/p>\n<p id=\"fs-idp46064432\">Press the down and up arrow keys to scroll.<\/p>\n<p id=\"fs-idp50820000\">\\(\\overline{x}\\) = 23.6, <em data-effect=\"italics\">M<\/em> = 24<\/p>\n<\/div>\n<div id=\"fs-idp48953680\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">Try It<\/div>\n<div id=\"fs-idm28353888\" data-type=\"exercise\">\n<div id=\"fs-idm72704208\" data-type=\"problem\">\n<p id=\"fs-idm46796800\">The following data show the number of months patients typically wait on a transplant list before getting surgery. The data are ordered from smallest to largest. Calculate the mean and median.<\/p>\n<p id=\"fs-idm114142640\"><span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">1 0\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">13\u00a0 <\/span><span data-type=\"item\">14\u00a0 <\/span><span data-type=\"item\">14\u00a0 <\/span><span data-type=\"item\">15\u00a0 <\/span><span data-type=\"item\">15\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">18\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">22\u00a0 <\/span><span data-type=\"item\">22\u00a0 <\/span><span data-type=\"item\">23\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">24<\/span><\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"element-231\" class=\"textbox textbox--examples\" data-type=\"example\">\n<div id=\"exer6\" data-type=\"exercise\">\n<div id=\"id45393377\" data-type=\"problem\">\n<p id=\"element-213\">Suppose that in a small town of 50 people, one person earns \\$5,000,000 per year and the other 49 each earn \\$30,000. Which is the better measure of the &#8220;center&#8221;: the mean or the median?<\/p>\n<\/div>\n<div id=\"id45393396\" data-type=\"solution\">\n<p id=\"element-444\">\\(\\overline{x}=\\frac{5,000,000+49\\left(30,000\\right)}{50}=129,400\\)<\/p>\n<p><em data-effect=\"italics\">M<\/em> = 30,000<\/p>\n<p id=\"element-831\">(There are 49 people who earn \\$30,000 and one person who earns \\$5,000,000.)<\/p>\n<p>The median is a better measure of the &#8220;center&#8221; than the mean because 49 of the values are 30,000 and one is 5,000,000. The 5,000,000 is an outlier. The 30,000 gives us a better sense of the middle of the data.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp18783360\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">Try It<\/div>\n<div id=\"fs-idm79009152\" data-type=\"exercise\">\n<div id=\"fs-idm79009024\" data-type=\"problem\">\n<p id=\"fs-idm10019504\">In a sample of 60 households, one house is worth \\$2,500,000. Half of the rest are worth \\$280,000, and all the others are worth \\$315,000. Which is the better measure of the \u201ccenter\u201d: the mean or the median?<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"element-584\">Another measure of the center is the mode. The <span data-type=\"term\">mode<\/span> is the most frequent value. There can be more than one mode in a data set as long as those values have the same frequency and that frequency is the highest. A data set with two modes is called bimodal.<\/p>\n<div id=\"element-114\" class=\"textbox textbox--examples\" data-type=\"example\">\n<p id=\"element-639\">Statistics exam scores for 20 students are as follows:<\/p>\n<p id=\"element-104\"><span id=\"set-536\" data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">50\u00a0 <\/span><span data-type=\"item\">53\u00a0 <\/span><span data-type=\"item\">59\u00a0 <\/span><span data-type=\"item\">59\u00a0 <\/span><span data-type=\"item\">63\u00a0 <\/span><span data-type=\"item\">63\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">72\u00a0 <\/span><span data-type=\"item\">76\u00a0 <\/span><span data-type=\"item\">78\u00a0 <\/span><span data-type=\"item\">81\u00a0 <\/span><span data-type=\"item\">83\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">84\u00a0 <\/span><span data-type=\"item\">90\u00a0 <\/span><span data-type=\"item\">93<\/span><\/span><\/p>\n<div id=\"exer3\" data-type=\"exercise\">\n<div id=\"id44835721\" data-type=\"problem\">\n<p id=\"element-32535\">Find the mode.<\/p>\n<\/div>\n<div id=\"id44835735\" data-type=\"solution\">\n<p id=\"element-76\">The most frequent score is 72, which occurs five times. Mode = 72.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp45793968\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">Try It<\/div>\n<div id=\"fs-idm24402032\" data-type=\"exercise\">\n<div id=\"fs-idm24643648\" data-type=\"problem\">\n<p id=\"fs-idp74555792\">The number of books checked out from the library from 25 students are as follows:<\/p>\n<p id=\"fs-idm901328\"><span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">0\u00a0 <\/span><span data-type=\"item\">1\u00a0 <\/span><span data-type=\"item\">2\u00a0 <\/span><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">3\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">4\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">5\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">7\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">8\u00a0 <\/span><span data-type=\"item\">9\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">10\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">11\u00a0 <\/span><span data-type=\"item\">12\u00a0 <\/span><span data-type=\"item\">12<\/span><\/span><span data-type=\"newline\"><br \/>\n<\/span>Find the mode.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"element-725\" class=\"textbox textbox--examples\" data-type=\"example\">\n<p id=\"element-622\">Five real estate exam scores are 430, 430, 480, 480, 495. The data set is bimodal because the scores 430 and 480 each occur twice.<\/p>\n<p id=\"element-353\">When is the mode the best measure of the &#8220;center&#8221;? Consider a weight loss program that advertises a mean weight loss of six pounds the first week of the program. The mode might indicate that most people lose two pounds the first week, making the program less appealing.<\/p>\n<div data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">NOTE<\/div>\n<p id=\"fs-idm78257648\">The mode can be calculated for qualitative data as well as for quantitative data. For example, if the data set is: red, red, red, green, green, yellow, purple, black, blue, the mode is red.<\/p>\n<\/div>\n<p id=\"element-660\" class=\"finger\">Statistical software will easily calculate the mean, the median, and the mode. Some graphing calculators can also make these calculations. In the real world, people make these calculations using software.<\/p>\n<\/div>\n<div id=\"fs-idp55881696\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">Try It<\/div>\n<div id=\"fs-idm2098096\" data-type=\"exercise\">\n<div id=\"fs-idm2097968\" data-type=\"problem\">\n<p id=\"fs-idm5923360\">Five credit scores are 680, 680, 700, 720, 720. The data set is bimodal because the scores 680 and 720 each occur twice. Consider the annual earnings of workers at a factory. The mode is \\$25,000 and occurs 150 times out of 301. The median is \\$50,000 and the mean is \\$47,500. What would be the best measure of the \u201ccenter\u201d?<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"element-282\" class=\"bc-section section\" data-depth=\"1\"><\/div>\n<div id=\"eip-529\" class=\"bc-section section\" data-depth=\"1\">\n<p>&nbsp;<\/p>\n<p id=\"eip-309\">A <strong>statistic<\/strong> is a number calculated from a sample. Statistic examples include the mean, the median and the mode as well as others. The sample mean \\(\\overline{x}\\) is an example of a statistic which estimates the population mean <em data-effect=\"italics\">\u03bc<\/em>.<\/p>\n<\/div>\n<div id=\"fs-idp28527728\" class=\"bc-section section\" data-depth=\"1\">\n<h3 data-type=\"title\">Calculating the Mean of Grouped Frequency Tables<\/h3>\n<p id=\"fs-idp16870784\">When only grouped data is available, you do not know the individual data values (we only know intervals and interval frequencies); therefore, you cannot compute an exact mean for the data set. What we must do is estimate the actual mean by calculating the mean of a frequency table. A frequency table is a data representation in which grouped data is displayed along with the corresponding frequencies. To calculate the mean from a grouped frequency table we can apply the basic definition of mean: <em data-effect=\"italics\">mean<\/em> = \\(\\frac{data\\text{\u00a0}sum}{number\\text{\u00a0}of\\text{\u00a0}data\\text{\u00a0}values}\\) We simply need to modify the definition to fit within the restrictions of a frequency table.<\/p>\n<p id=\"fs-idp28261664\">Since we do not know the individual data values we can instead find the midpoint of each interval. The midpoint is \\(\\frac{lower\\text{\u00a0}boundary+upper\\text{\u00a0}boundary}{2}\\). We can now modify the mean definition to be \\(Mean\\text{\u00a0}of\\text{\u00a0}Frequency\\text{\u00a0}Table=\\frac{\\sum fm}{\\sum f}\\) where <em data-effect=\"italics\">f<\/em> = the frequency of the interval and <em data-effect=\"italics\">m<\/em> = the midpoint of the interval.<\/p>\n<div id=\"fs-idp59127680\" class=\"textbox textbox--examples\" data-type=\"example\">\n<div id=\"fs-idp61839840\" data-type=\"exercise\">\n<div id=\"fs-idp47622112\" data-type=\"problem\">\n<p id=\"fs-idm6896112\">A frequency table displaying professor Blount\u2019s last statistic test is shown. Find the best estimate of the class mean.<\/p>\n<table id=\"fs-idp32456976\" summary=\"\">\n<thead>\n<tr>\n<th>Grade Interval<\/th>\n<th>Number of Students<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>50\u201356.5<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>56.5\u201362.5<\/td>\n<td>0<\/td>\n<\/tr>\n<tr>\n<td>62.5\u201368.5<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>68.5\u201374.5<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>74.5\u201380.5<\/td>\n<td>2<\/td>\n<\/tr>\n<tr>\n<td>80.5\u201386.5<\/td>\n<td>3<\/td>\n<\/tr>\n<tr>\n<td>86.5\u201392.5<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>92.5\u201398.5<\/td>\n<td>1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-idp56820112\" data-type=\"solution\">\n<ul id=\"fs-idp26414448\">\n<li>Find the midpoints for all intervals<\/li>\n<\/ul>\n<table id=\"fs-idp15194576\" summary=\"\">\n<thead>\n<tr>\n<th>Grade Interval<\/th>\n<th>Midpoint<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>50\u201356.5<\/td>\n<td>53.25<\/td>\n<\/tr>\n<tr>\n<td>56.5\u201362.5<\/td>\n<td>59.5<\/td>\n<\/tr>\n<tr>\n<td>62.5\u201368.5<\/td>\n<td>65.5<\/td>\n<\/tr>\n<tr>\n<td>68.5\u201374.5<\/td>\n<td>71.5<\/td>\n<\/tr>\n<tr>\n<td>74.5\u201380.5<\/td>\n<td>77.5<\/td>\n<\/tr>\n<tr>\n<td>80.5\u201386.5<\/td>\n<td>83.5<\/td>\n<\/tr>\n<tr>\n<td>86.5\u201392.5<\/td>\n<td>89.5<\/td>\n<\/tr>\n<tr>\n<td>92.5\u201398.5<\/td>\n<td>95.5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<ul id=\"fs-idp72598816\">\n<li>Calculate the sum of the product of each interval frequency and midpoint.\\({\\sum }^{\\text{\u200b}}fm\\)\\(53.25\\left(1\\right)+59.5\\left(0\\right)+65.5\\left(4\\right)+71.5\\left(4\\right)+77.5\\left(2\\right)+83.5\\left(3\\right)+89.5\\left(4\\right)+95.5\\left(1\\right)=1460.25\\)<\/li>\n<li>\\(\\mu =\\frac{\\sum fm}{\\sum f}=\\frac{1460.25}{19}=76.86\\)<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idm52755520\" class=\"statistics try\" data-type=\"note\" data-has-label=\"true\" data-label=\"\">\n<div data-type=\"title\">Try It<\/div>\n<div id=\"fs-idp22476928\" data-type=\"exercise\">\n<div id=\"fs-idp50951968\" data-type=\"problem\">\n<p id=\"fs-idm11216000\">Maris conducted a study on the effect that playing video games has on memory recall. As part of her study, she compiled the following data:<\/p>\n<table id=\"fs-idm6918832\" summary=\"\">\n<thead>\n<tr>\n<th>Hours Teenagers Spend on Video Games<\/th>\n<th>Number of Teenagers<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>0\u20133.5<\/td>\n<td>3<\/td>\n<\/tr>\n<tr>\n<td>3.5\u20137.5<\/td>\n<td>7<\/td>\n<\/tr>\n<tr>\n<td>7.5\u201311.5<\/td>\n<td>12<\/td>\n<\/tr>\n<tr>\n<td>11.5\u201315.5<\/td>\n<td>7<\/td>\n<\/tr>\n<tr>\n<td>15.5\u201319.5<\/td>\n<td>9<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-idp10596832\">What is the best estimate for the mean number of hours spent playing video games?<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp2891248\" class=\"footnotes\" data-depth=\"1\">\n<h3 data-type=\"title\">References<\/h3>\n<p id=\"fs-idp41166864\">Data from The World Bank, available online at http:\/\/www.worldbank.org (accessed April 3, 2013).<\/p>\n<p id=\"fs-idp18149184\">\u201cDemographics: Obesity \u2013 adult prevalence rate.\u201d Indexmundi. Available online at http:\/\/www.indexmundi.com\/g\/r.aspx?t=50&amp;v=2228&amp;l=en (accessed April 3, 2013).<\/p>\n<\/div>\n<div id=\"fs-idm7033248\" class=\"summary\" data-depth=\"1\">\n<h3 data-type=\"title\">Chapter Review<\/h3>\n<p id=\"fs-idm18283152\">The mean and the median can be calculated to help you find the &#8220;center&#8221; of a data set. The mean is the best estimate for the actual data set, but the median is the best measurement when a data set contains several outliers or extreme values. The mode will tell you the most frequently occuring datum (or data) in your data set. The mean, median, and mode are extremely helpful when you need to analyze your data, but if your data set consists of ranges which lack specific values, the mean may seem impossible to calculate. However, the mean can be approximated if you add the lower boundary with the upper boundary and divide by two to find the midpoint of each interval. Multiply each midpoint by the number of values found in the corresponding range. Divide the sum of these values by the total number of data values in the set.<\/p>\n<\/div>\n<div id=\"fs-idm345328\" class=\"formula-review\" data-depth=\"1\">\n<h3 data-type=\"title\">Formula Review<\/h3>\n<p id=\"fs-idp28375264\">\\(\\mu =\\frac{\\sum fm}{\\sum f}\\) Where <em data-effect=\"italics\">f<\/em> = interval frequencies and <em data-effect=\"italics\">m<\/em> = interval midpoints.<\/p>\n<\/div>\n<div id=\"fs-idp67676496\" class=\"practice\" data-depth=\"1\">\n<div id=\"fs-idp11191056\" data-type=\"exercise\">\n<div id=\"fs-idp72176256\" data-type=\"problem\">\n<p id=\"fs-idp29942336\">Find the mean for the following frequency tables.<\/p>\n<ol id=\"fs-idp39027888\" type=\"a\">\n<li>\n<table id=\"fs-idp4665840\" summary=\"\">\n<thead>\n<tr>\n<th>Grade<\/th>\n<th>Frequency<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>49.5\u201359.5<\/td>\n<td>2<\/td>\n<\/tr>\n<tr>\n<td>59.5\u201369.5<\/td>\n<td>3<\/td>\n<\/tr>\n<tr>\n<td>69.5\u201379.5<\/td>\n<td>8<\/td>\n<\/tr>\n<tr>\n<td>79.5\u201389.5<\/td>\n<td>12<\/td>\n<\/tr>\n<tr>\n<td>89.5\u201399.5<\/td>\n<td>5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>\n<table id=\"fs-idp21318848\" summary=\"\">\n<thead>\n<tr>\n<th>Daily Low Temperature<\/th>\n<th>Frequency<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>49.5\u201359.5<\/td>\n<td>53<\/td>\n<\/tr>\n<tr>\n<td>59.5\u201369.5<\/td>\n<td>32<\/td>\n<\/tr>\n<tr>\n<td>69.5\u201379.5<\/td>\n<td>15<\/td>\n<\/tr>\n<tr>\n<td>79.5\u201389.5<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>89.5\u201399.5<\/td>\n<td>0<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>\n<table id=\"fs-idp49142800\" summary=\"\">\n<thead>\n<tr>\n<th>Points per Game<\/th>\n<th>Frequency<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>49.5\u201359.5<\/td>\n<td>14<\/td>\n<\/tr>\n<tr>\n<td>59.5\u201369.5<\/td>\n<td>32<\/td>\n<\/tr>\n<tr>\n<td>69.5\u201379.5<\/td>\n<td>15<\/td>\n<\/tr>\n<tr>\n<td>79.5\u201389.5<\/td>\n<td>23<\/td>\n<\/tr>\n<tr>\n<td>89.5\u201399.5<\/td>\n<td>2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"eip-193\"><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> The following data show the lengths of boats moored in a marina. The data are ordered from smallest to largest: <span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"><span data-type=\"item\">16\u00a0 <\/span><span data-type=\"item\">17\u00a0 <\/span><span data-type=\"item\">19\u00a0 <\/span><span data-type=\"item\">20\u00a0 <\/span><span data-type=\"item\">20\u00a0 <\/span><span data-type=\"item\">21\u00a0 <\/span><span data-type=\"item\">23\u00a0 <\/span><span data-type=\"item\">24\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">25\u00a0 <\/span><span data-type=\"item\">26\u00a0 <\/span><span data-type=\"item\">26\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">27\u00a0 <\/span><span data-type=\"item\">28\u00a0 <\/span><span data-type=\"item\">29\u00a0 <\/span><span data-type=\"item\">30\u00a0 <\/span><span data-type=\"item\">32\u00a0 <\/span><span data-type=\"item\">33\u00a0 <\/span><span data-type=\"item\">33\u00a0 <\/span><span data-type=\"item\">34\u00a0 <\/span><span data-type=\"item\">35\u00a0 <\/span><span data-type=\"item\">37\u00a0 <\/span><span data-type=\"item\">39\u00a0 <\/span><span data-type=\"item\">40<\/span><\/span><\/p>\n<div id=\"fs-idp3713376\" data-type=\"exercise\">\n<div id=\"fs-idp45051248\" data-type=\"problem\">\n<p id=\"fs-idp72372672\">Calculate the mean.<\/p>\n<\/div>\n<div id=\"fs-idp54737296\" data-type=\"solution\">\n<p id=\"fs-idp31759600\">Mean: 16 + 17 + 19 + 20 + 20 + 21 + 23 + 24 + 25 + 25 + 25 + 26 + 26 + 27 + 27 + 27 + 28 + 29 + 30 + 32 + 33 + 33 + 34 + 35 + 37 + 39 + 40 = 738;<\/p>\n<p id=\"fs-idp62762816\">\\(\\frac{738}{27}\\) = 27.33<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-idp23937584\" data-type=\"exercise\">\n<div id=\"fs-idm6016496\" data-type=\"problem\">\n<p id=\"fs-idp65368416\">Identify the median.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-idm35941040\" data-type=\"exercise\">\n<div id=\"fs-idp155088\" data-type=\"problem\">\n<p id=\"fs-idp27706128\">Identify the mode.<\/p>\n<\/div>\n<div id=\"fs-idm53012848\" data-type=\"solution\">\n<p id=\"fs-idp8367280\">The most frequent lengths are 25 and 27, which occur three times. Mode = 25, 27<\/p>\n<\/div>\n<\/div>\n<p id=\"fs-idp43142960\"><span data-type=\"newline\"><br \/>\n<\/span><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people answered that they generally sell three cars; nineteen generally sell four cars; twelve generally sell five cars; nine generally sell six cars; eleven generally sell seven cars. Calculate the following:<\/p>\n<div data-type=\"exercise\">\n<div id=\"id5461618\" data-type=\"problem\">\n<p>sample mean = \\(\\overline{x}\\) = _______<\/p>\n<\/div>\n<\/div>\n<div id=\"eip-83\" data-type=\"exercise\">\n<div id=\"eip-718\" data-type=\"problem\">\n<p id=\"eip-423\">median = _______<\/p>\n<\/div>\n<div id=\"eip-288\" data-type=\"solution\">\n<p id=\"eip-669\">4<\/p>\n<\/div>\n<\/div>\n<div id=\"eip-630\" data-type=\"exercise\">\n<div id=\"eip-353\" data-type=\"problem\">\n<p id=\"eip-212\">mode = _______<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idm59277808\" class=\"free-response\" data-depth=\"1\">\n<h3 data-type=\"title\">Homework<\/h3>\n<div data-type=\"exercise\">\n<div data-type=\"problem\">\n<p id=\"eip-474\">1) \u00a0<a class=\"autogenerated-content\" href=\"#eip-456s\">(Figure)<\/a> gives the percent of children under five considered to be underweight. What is the best estimate for the mean percentage of underweight children?<\/p>\n<table id=\"eip-456s\" summary=\"Table....\">\n<thead>\n<tr>\n<th>Percent of Underweight Children<\/th>\n<th>Number of Countries<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>16\u201321.45<\/td>\n<td>23<\/td>\n<\/tr>\n<tr>\n<td>21.45\u201326.9<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>26.9\u201332.35<\/td>\n<td>9<\/td>\n<\/tr>\n<tr>\n<td>32.35\u201337.8<\/td>\n<td>7<\/td>\n<\/tr>\n<tr>\n<td>37.8\u201343.25<\/td>\n<td>6<\/td>\n<\/tr>\n<tr>\n<td>43.25\u201348.7<\/td>\n<td>1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"eip-492\" data-type=\"solution\">\n<p>&nbsp;<\/p>\n<p id=\"eip-506\">2)\u00a0 The most obese countries in the world have obesity rates that range from 11.4% to 74.6%. This data is summarized in the following table.<\/p>\n<table id=\"eip-456\" summary=\"Table....\">\n<thead>\n<tr>\n<th>Percent of Population Obese<\/th>\n<th>Number of Countries<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>11.4\u201320.45<\/td>\n<td>29<\/td>\n<\/tr>\n<tr>\n<td>20.45\u201329.45<\/td>\n<td>13<\/td>\n<\/tr>\n<tr>\n<td>29.45\u201338.45<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>38.45\u201347.45<\/td>\n<td>0<\/td>\n<\/tr>\n<tr>\n<td>47.45\u201356.45<\/td>\n<td>2<\/td>\n<\/tr>\n<tr>\n<td>56.45\u201365.45<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>65.45\u201374.45<\/td>\n<td>0<\/td>\n<\/tr>\n<tr>\n<td>74.45\u201383.45<\/td>\n<td>1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<ol id=\"eip-idm42348400\" type=\"a\">\n<li>What is the best estimate of the average obesity percentage for these countries?<\/li>\n<li>The United States has an average obesity rate of 33.9%. Is this rate above average or below?<\/li>\n<li>How does the United States compare to other countries?<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idm1725088\" class=\"bring-together-homework\" data-depth=\"1\">\n<h3 data-type=\"title\">Bringing It Together<\/h3>\n<div id=\"element-832\" data-type=\"exercise\">\n<div id=\"id6092616\" data-type=\"problem\">\n<div id=\"eip-idm179364784\" class=\"bc-figure figure\"><\/div>\n<\/div>\n<\/div>\n<p id=\"fs-idm4887840\"><em data-effect=\"italics\">Use the following information to answer the next three exercises<\/em>: We are interested in the number of years students in a particular elementary statistics class have lived in California. The information in the following table is from the entire section.<\/p>\n<table id=\"element-368\" summary=\"This table presents the number of years students in a statistics class have lived in California. The first column lists the number of years and the second column lists the frequency.\">\n<thead>\n<tr>\n<th>Number of years<\/th>\n<th>Frequency<\/th>\n<th>Number of years<\/th>\n<th>Frequency<\/th>\n<\/tr>\n<\/thead>\n<tfoot>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td>Total = 20<\/td>\n<\/tr>\n<\/tfoot>\n<tbody>\n<tr>\n<td>7<\/td>\n<td>1<\/td>\n<td>22<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>14<\/td>\n<td>3<\/td>\n<td>23<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>15<\/td>\n<td>1<\/td>\n<td>26<\/td>\n<td>1<\/td>\n<\/tr>\n<tr>\n<td>18<\/td>\n<td>1<\/td>\n<td>40<\/td>\n<td>2<\/td>\n<\/tr>\n<tr>\n<td>19<\/td>\n<td>4<\/td>\n<td>42<\/td>\n<td>2<\/td>\n<\/tr>\n<tr>\n<td>20<\/td>\n<td>3<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<div data-type=\"exercise\">\n<div id=\"id4699277\" data-type=\"problem\">\n<p>3)\u00a0 What is the <em data-effect=\"italics\">IQR<\/em>?<\/p>\n<ol id=\"ni1\" type=\"a\" data-mark-suffix=\".\">\n<li>8<\/li>\n<li>11<\/li>\n<li>15<\/li>\n<li>35<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6016838\" data-type=\"solution\">\n<p id=\"element-991\">\n<\/div>\n<\/div>\n<div data-type=\"exercise\">\n<div id=\"id4942656\" data-type=\"problem\">\n<p id=\"element-780\">4)\u00a0 What is the mode?<\/p>\n<ol id=\"ni2\" type=\"a\" data-mark-suffix=\".\">\n<li>19<\/li>\n<li>19.5<\/li>\n<li>14 and 20<\/li>\n<li>22.65<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"element-346\" data-type=\"exercise\">\n<div id=\"id5971682\" data-type=\"problem\">\n<p>&nbsp;<\/p>\n<p>5)\u00a0 Is this a sample or the entire population?<\/p>\n<ol id=\"ni3\" type=\"a\" data-mark-suffix=\".\">\n<li>sample<\/li>\n<li>entire population<\/li>\n<li>neither<\/li>\n<\/ol>\n<\/div>\n<div id=\"id4081124\" data-type=\"solution\">\n<p id=\"element-366\">\n<\/div>\n<\/div>\n<p id=\"JavErc\">6) Javier and Ercilia are supervisors at a shopping mall. Each was given the task of estimating the mean distance that shoppers live from the mall. They each randomly surveyed 100 shoppers. The samples yielded the following information.<\/p>\n<table summary=\"This table presents two shopping mall supervisors and their estimations of the mean distance shoppers live from the mall. Javier's data is in the second column and Ercilia is in the third column. The first row is for sample means and the second row is for standard deviations.\">\n<thead>\n<tr>\n<th><\/th>\n<th>Javier<\/th>\n<th>Ercilia<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>\\(\\overline{x}\\)<\/td>\n<td>6.0 miles<\/td>\n<td>6.0 miles<\/td>\n<\/tr>\n<tr>\n<td>\\(s\\)<\/td>\n<td>4.0 miles<\/td>\n<td>7.0 miles<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<ol type=\"a\">\n<li>How can you determine which survey was correct ?<\/li>\n<li>Explain what the difference in the results of the surveys implies about the data.<\/li>\n<li>If the two histograms depict the distribution of values for each supervisor, which one depicts Ercilia&#8217;s sample? How do you know?<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<div id=\"eip-idm218452576\" class=\"bc-figure figure\"><span id=\"id8387446\" data-type=\"media\" data-display=\"block\" data-alt=\"This shows two histograms. The first histogram shows a fairly symmetrical distribution with a mode of 6. The second histogram shows a uniform distribution.\"><img decoding=\"async\" src=\"https:\/\/pressbooks.ccconline.org\/acccomposition1\/wp-content\/uploads\/sites\/83\/2022\/05\/fig-ch02_13_09-1.jpg\" alt=\"This shows two histograms. The first histogram shows a fairly symmetrical distribution with a mode of 6. The second histogram shows a uniform distribution.\" width=\"450\" data-media-type=\"image\/jpg\" \/><\/span><\/div>\n<\/li>\n<li>If the two box plots depict the distribution of values for each supervisor, which one depicts Ercilia\u2019s sample? How do you know?<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<div class=\"bc-figure figure\"><span id=\"id8629835\" data-type=\"media\" data-display=\"block\" data-alt=\"This shows two horizontal boxplots. The first boxplot is graphed over a number line from 0 to 21. The first whisker extends from 0 to 1. The box begins at the first quartile, 1, and ends at the third quartile, 14. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 21. The second boxplot is graphed over a number line from 0 to 12. The first whisker extends from 0 to 4. The box begins at the first quartile, 4, and ends at the third quartile, 9. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 12.\"><img decoding=\"async\" src=\"https:\/\/pressbooks.ccconline.org\/acccomposition1\/wp-content\/uploads\/sites\/83\/2022\/08\/fig-ch02_13_10-1.jpg\" alt=\"This shows two horizontal boxplots. The first boxplot is graphed over a number line from 0 to 21. The first whisker extends from 0 to 1. The box begins at the first quartile, 1, and ends at the third quartile, 14. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 21. The second boxplot is graphed over a number line from 0 to 12. The first whisker extends from 0 to 4. The box begins at the first quartile, 4, and ends at the third quartile, 9. A vertical, dashed line marks the median at 6. The second whisker extends from the third quartile to the largest value, 12.\" width=\"450\" data-media-type=\"image\/jpg\" \/><\/span><\/div>\n<\/li>\n<\/ol>\n<div data-type=\"exercise\">\n<div data-type=\"solution\">\n<p><strong>Answers to odd Questions<\/strong><\/p>\n<p>1)\u00a0 The mean percentage, \\(\\overline{x}=\\frac{1328.65}{50}=26.75\\)<\/p>\n<p>3) a<\/p>\n<p>5) b<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\" data-type=\"glossary\">\n<h3 data-type=\"glossary-title\">Glossary<\/h3>\n<dl id=\"fs-idm7751856\">\n<dt>Frequency Table<\/dt>\n<dd id=\"fs-idp28775440\">a data representation in which grouped data is displayed along with the corresponding frequencies<\/dd>\n<\/dl>\n<dl id=\"mean\">\n<dt>Mean<\/dt>\n<dd id=\"id10578364\">a number that measures the central tendency of the data; a common name for mean is &#8216;average.&#8217; The term &#8216;mean&#8217; is a shortened form of &#8216;arithmetic mean.&#8217; By definition, the mean for a sample (denoted by \\(\\overline{x}\\)) is \\(\\overline{x}\\text{\u00a0}=\\text{\u00a0}\\frac{\\text{Sum\u00a0of\u00a0all\u00a0values\u00a0in\u00a0the\u00a0sample}}{\\text{Number\u00a0of\u00a0values\u00a0in\u00a0the\u00a0sample}}\\), and the mean for a population (denoted by <em data-effect=\"italics\">\u03bc<\/em>) is \\(\\mu =\\frac{\\text{Sum\u00a0of\u00a0all\u00a0values\u00a0in\u00a0the\u00a0population}}{\\text{Number\u00a0of\u00a0values\u00a0in\u00a0the\u00a0population}}\\).<\/dd>\n<\/dl>\n<dl id=\"median\">\n<dt>Median<\/dt>\n<dd id=\"id44836016\">a number that separates ordered data into halves; half the values are the same number or smaller than the median and half the values are the same number or larger than the median. The median may or may not be part of the data.<\/dd>\n<\/dl>\n<dl id=\"fs-idp5033152\">\n<dt>Midpoint<\/dt>\n<dd id=\"fs-idp75012256\">the mean of an interval in a frequency table<\/dd>\n<\/dl>\n<dl id=\"mode\">\n<dt>Mode<\/dt>\n<dd id=\"id44836043\">the value that appears most frequently in a set of data<\/dd>\n<\/dl>\n<\/div>\n","protected":false},"author":32,"menu_order":4,"template":"","meta":{"pb_show_title":"","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-97","chapter","type-chapter","status-publish","hentry"],"part":51,"_links":{"self":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapters\/97","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/wp\/v2\/users\/32"}],"version-history":[{"count":5,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapters\/97\/revisions"}],"predecessor-version":[{"id":702,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapters\/97\/revisions\/702"}],"part":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/parts\/51"}],"metadata":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapters\/97\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/wp\/v2\/media?parent=97"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/pressbooks\/v2\/chapter-type?post=97"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/wp\/v2\/contributor?post=97"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.ccconline.org\/accintrostats\/wp-json\/wp\/v2\/license?post=97"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}